Thmyl Brnamj Zf Awrj Ly Alkybwrd Kn2000 〈99% Easy〉

b↔y r↔i n↔m a↔z m↔n j↔q → yimznq

Given kn2000 , might be in 2000 ? If kn = in, then k→i (-2), n→n (0) not consistent. Let’s check ly again: if ly = of (common): l (12) → o (15) = +3, y (25) → f (6) = 25+3=28 mod 26=2→b? No, that's wrong. Given the complexity, I suspect it's a Caesar shift of +5 (decrypt by -5): thmyl brnamj zf awrj ly alkybwrd kn2000

ROT13 on thmyl : t→g, h→u, m→z, y→l, l→y → guzly (no). b↔y r↔i n↔m a↔z m↔n j↔q → yimznq

thmyl → g s n b o? Let's do systematically: t (20) ↔ g (7) h (8) ↔ s (19) m (13) ↔ n (14) y (25) ↔ b (2) l (12) ↔ o (15) So thmyl → gsnbo (not English). No, that's wrong